前面一篇文章小编为大家讲解的是类比推理，今天要为大家讲解的是统计枚举推理。这种推理模式在考试中也是经常遇到的，希望通过小编的讲解大家能够加深认识。
一、GMAT逻辑统计枚举推理的定义
1、定义：枚举归纳推理是由所见的某一类事物的部分分子具有某种属性，而且没有遇到相反的情况，于是得出这一类事务都是具有这种属性的一般性结论。枚举归纳推理的结论是或然的，它的可靠程度是和事例数量相关的。
2、特点：前提的范畴将会在结论中被扩大，简单来说就是由样本推总体。比如，我们在上海卢湾区做了一项调查，发现有 90%的人患有病 A，结论就是在整个上海市也有 90%的人患有病 A。
3、形式：Premise：A中有N%是B。Conclusion：A+C中有N%是B)。
(详情请看 GMAT逻辑统计枚举推理解题法 )
二、GMAT逻辑统计枚举推理的解题技巧
1、正确答案的方向。
CQ1：样本是否具有代表性?是不是用来推理的样本是特殊的?加强就说这个样本具有代表性，削弱就说这个样本不具有代表性，或者具有特殊性。
CQ2：样本的数量是否足够?削弱的话，可以举另一个例子D中并不是有N%的是B。
2、解题方法：只要是统计枚举模式的推理，答案选择中必须出现“样本”，就是抽象形式中的A。
(详情请看 GMAT逻辑七大推理模式详解 )
三、GMAT逻辑链充分必要条件举例分析
例一：
A recent report determined that although only 3 percent of drivers on Maryland highways equipped their vehicles with radar detectors, 33 percent of all vehicles ticketed for exceeding the speed limit were equipped with them. Clearly, drivers who equip their vehicles with radar detectors are more likely to exceed the speed limit regularly than are drivers who do not.
The conclusion drawn above depends on which of the following assumptions?
(A) Drivers who equip their vehicles with radar detectors are less likely to be ticketed for exceeding the speed limit than are drivers who do not.
(B) Drivers who are ticketed for exceeding the speed limit are more likely to exceed the speed limit regularly than are drivers who are not ticketed.
(C) The number of vehicles that were ticketed for exceeding the speed limit was greater than the number of vehicles that were equipped with radar detectors.
(D) Many of the vehicles that were ticketed for exceeding the speed limit were ticketed more than once in the time period covered by the report.
(E) Drivers on Maryland highways exceeded the speed limit more often than did drivers on other state highways not covered in the report.
统计枚举推理分析：
相关因果，本题要削弱drivers who equip their vehicles with radar detectors are less likely to exceed the speed limit regularly than are drivers who do not.
抓住果，谈到因果关系的或者解释果的选项留下。
A 谈到了装雷达和超速，先留着。
B 没谈到雷达。
C 本题讨论的是装雷达与否与超速的联系，而不是超速与装雷达的联系，不能削弱。
D 解释了果，留着。
E 没谈到雷达。
比较AD，A说的是装了雷达更不容易被抄牌，但是题中却说装雷达在车中的比例远低于装雷达的车被抄牌在所有被抄牌车的比例，因此不合;而D说装了雷达的被抄牌几次，因此削弱了less likely to exceed…答案为D。
例二：
Often patients with ankle fractures that are stable, and thus do not require surgery, are given follow-up x-rays because their orthopedists are concerned about possibly having misjudged the stability of the fracture. When a number of follow-up x-rays were reviewed, however, all the fractures that had initially been judged stable were found to have healed correctly. Therefore, it is a waste of money to order follow-up x-rays of ankle fracture initially judged stable.
Which of the following, if true, most strengthens the argument?
A. Doctors who are general practitioners rather than orthopedists are less likely than orthopedists to judge the stability of an ankle fracture correctly.(全科医生的判断没有骨科医生那么准确，但并没有提到样本 a number of follow-up x-rays，所以既不是加强也不是削弱)
B. Many ankle injuries for which an initial x-ray is ordered are revealed by the x-ray not to involve any fracture of the ankle.
C. X-rays of patients of many different orthopedists working in several hospitals were reviewed. (只有这个选项是有 a number of follow-up x-rays，说的是不同的医生看的，显然是唯一的答案。)
D. The healing of ankle fractures that have been surgically repaired is always checked by means of a follow-up x-ray.
E. Orthopedists routinely order follow-up x-rays for fractures of bone other than ankle bones.
统计枚举推理分析：
通读原文，找到结论句：Therefore, it is a waste of money to order follow-up x-rays of ankle fracture initially judged stable.
看前提：When a number of follow-up x-rays were reviewed, however, all the fractures that had initially been judged stable were found to have healed correctly.
逻辑链(前提和结论之间的推理关系)：因为reviewed的样本a number of follow-up x-rays是 have healed correctly，所以结论说it is a waste of money to order follow-up x-rays of ankle fracture initially judged stable，意思就是所有的 x-rays 都应该是 have healed correctly。
看问题：问题让我们加强，那么就是说这个样本是具有代表性的，可以推而广之。
找选项：提到这个样本的代表性的。
GMAT逻辑解题原则前程百利小编为大家简单介绍这些，遵循逻辑解题的客观性原则是前提也是基础，在客观的基础上利用技巧去高效地排除错误选项是逻辑解题的关键，希望大家能够重视。
(详情请看 GMAT逻辑练习题)
以上两篇文章为大家简单讲解了统计枚举推理的解题方法和题型特点，大家可以稍作了解这种分析方法，利用它的CQ模式解题。
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